D.ershane Solutions Ddili.org

Arrays

  1. import std.stdio;
    import std.algorithm;
    
    void main() {
        write("How many values will be entered? ");
        int count;
        readf(" %s", &count);
    
        double[] values;
        values.length = count;
    
        // The counter is commonly named as 'i'
        int i;
        while (i < count) {
            write("Value ", i, ": ");
            readf(" %s", &values[i]);
            ++i;
        }
    
        writeln("In sorted order:");
        sort(values);
    
        i = 0;
        while (i < count) {
            write(values[i], " ");
            ++i;
        }
        writeln();
    
        writeln("In reverse order:");
        reverse(values);
    
        i = 0;
        while (i < count) {
            write(values[i], " ");
            ++i;
        }
        writeln();
    }
    
  2. The explanations are included as code comments:
    import std.stdio;
    import std.algorithm;
    
    void main() {
        // Using dynamic arrays because it is not known how many
        // values are going to be read from the input
        int[] odds;
        int[] evens;
    
        writeln("Please enter integers (-1 to terminate):");
    
        while (true) {
    
            // Reading the value
            int value;
            readf(" %s", &value);
    
            // The special value of -1 breaks the loop
            if (value == -1) {
                break;
            }
    
            // Adding to the corresponding array, depending on
            // whether the value is odd or even. It is an even
            // number if there is no remainder when divided by 2.
            if ((value % 2) == 0) {
                evens ~= value;
    
            } else {
                odds ~= value;
            }
        }
    
        // The odds and evens arrays are sorted separately
        sort(odds);
        sort(evens);
    
        // The two arrays are then appended to form a new array
        int[] result;
        result = odds ~ evens;
    
        writeln("First the odds then the evens, sorted:");
    
        // Printing the array elements in a loop
        int i;
        while (i < result.length) {
            write(result[i], " ");
            ++i;
        }
    
        writeln();
    }
    
  3. There are three mistakes (bugs) in this program. The first two are with the while loops: Both of the loop conditions use the <= operator instead of the < operator. As a result, the program uses invalid indexes and attempts to access elements that are not parts of the arrays.

    Since it is more beneficial for you to debug the third mistake yourself, I would like you to first run the program after fixing the previous two bugs. You will notice that the program will not print the results. Can you figure out the remaining problem before reading the following paragraph?

    The value of i is 5 when the first while loop terminates, and that value is causing the logical expression of the second loop to be false, which in turn is preventing the second loop to be entered. The solution is to reset i to 0 before the second while loop, for example with the statement i = 0;